# String Ordered Permutation Algorithm Problem

### String Permutation Problem

The algorithm problem goes something like this:

If you are given a character and its possible substitution set, then write a function that would print all the permutation of its characters.

Eg.

Given word “java”

Substitution Set =>
j [“J”, “7”]
a [“@”, “J”, “9”]
v [“V”, “^”]

Based on this, the possible permutations could be: J@V@, 7JV9..

Here is my approach using java

``````
package com.gullele;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

/**
*
* @author kaleb@gullele.com
*
*/
public class PassPermutation {

/**
* Holds the result of the permutation
*/
private List result;

/**
*
* @param args
*/
public static void main(String[] args) {
PassPermutation word = new PassPermutation();
word.initializeResult();

List words = word.wordToListMapper("java");

word.permuteIt("", words, 0);

for (String str : word.result) {
System.out.println(str);;
}
}

/**
* Recursive function to handle the permutation.
* @param words
*/
private void permuteIt(String part, List words, int index) {
int size = words.size();
if (index == size-1) {
String word = words.get(words.size()-1);
for (int i=0 ; i < word.length() ; i++) {
}
} else {
String word = words.get(index);
index++;
for (int j=0 ; j < word.length() ; j++) {
part += word.charAt(j);
permuteIt(part, words, index);
part = part.substring(0, part.length()-1);
}
}
}

private void initializeResult() {
this.result = new ArrayList();
}

/**
* A word to its combination mapping
* @param word
* @return
*/
private List wordToListMapper(String word) {

Map mapper = this.dictionary();
List mapped = new ArrayList();

for (Character c:word.toCharArray()) {
if (mapper.containsKey(c)) {
}
}

return mapped;
}

/**
* A mapping dictionary.
* @return
*/
private Map dictionary() {

Map mapper = new HashMap();
mapper.put('j', "J7");
mapper.put('a', "@J9");
mapper.put('v', "v^");

return mapper;
}
}
```
```
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