undefined variable error javascript with php
you want to do something simple like passing variable like this
<?php $variable_name = "some value"; var some_var = <?=$variable_name" ?>;
but it didn’t work
Here is the solved version…
Very simple than you thought
<pre> $variable_name = "some value"; var some_var = "<?=$variable_name" ?>"; </pre>
yup, just quote it from left and right so that it wont be considered as string not JS variable. If the value in variable is number, there would not be any problem
See how you would solve these known algorithm problems
testing k complementary pairs algorithm with junitImplementing tokenizer and adding tokens to the linked list
Check if there are three numbers a, b, c giving a total T from array A
Finding missing numbers from billion sequential number list file
Check if two strings are anagrams or not
Array reversal in Recurrsion
Java solution for checking anagram strings – tell if phrases are anagrams
binary tree problems with solution
Get maximum occurring character
Find longest palindrom from sequence of characters
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Yoou reall mzke it seem sso easy wth your presentation
but I find this topic to bee reaply something which I think
I would never understand. It seems too complicated annd extremely road for
me. I am looking forward for your next post, I will try too gget the hang of it!
gullele
Am sorry about it being easy looking approach.. I will try to have another post with more elaboration